Given two attachment points, one 2 feet and the other 6 feet from the center of gravity, what is the weight distribution percentage for each point?

To determine the weight distribution percentage between two attachment points based on their distances from the center of gravity, the principle of leverage and moments can be applied. When an object is suspended or lifted from multiple points, the tension in each attachment point depends on its distance from the center of gravity.

In this scenario, one attachment point is 2 feet away from the center of gravity and the other is 6 feet away. The attachment point that is further from the center of gravity typically bears a greater share of the load due to the greater moment arm it creates. The closer point, having a shorter distance from the center of gravity, will carry less of the weight.

By using the inverse relationship between the distances and the weights at each point, we can calculate the weight distribution. The closer attachment point (2 feet) will take a smaller percentage of the weight, while the further one (6 feet) will take a larger share.

To illustrate this, we can sum the distances (2 + 6 = 8 feet). Each point's weight is then expressed as a percentage of the total effective distance from the center of gravity. The formula for finding the weight distribution at each point can be simplified to the concept that the share of weight at each point is